Statistics Quest

Simple exponential smoothing (SES)

A forecast for series without trend or seasonality: a weighted average of past observations with weights that decay geometrically, controlled by the smoothing parameter α.

ℓt=αyt+(1−α)ℓt−1=ℓt−1+αet,et=yt−ℓt−1\ell_t = \alpha y_t + (1-\alpha)\ell_{t-1} = \ell_{t-1} + \alpha e_t, \qquad e_t = y_t - \ell_{t-1}
Level update (weighted-average and error-correction forms)
ℓt\ell_t
smoothed level after observing yty_t
α\alpha
smoothing parameter, 0<alpha<10 < alpha < 1; larger values follow recent data more closely
ete_t
one-step-ahead forecast error
y^T+h∣T=ℓT,σh2=σ^2(1+α2(h−1)),σ^2=SSET−2\hat y_{T+h \given T} = \ell_T, \qquad \sigma_h^2 = \hat\sigma^2\left(1 + \alpha^2(h-1)\right), \quad \hat\sigma^2 = \frac{\text{SSE}}{T-2}
Flat forecasts and approximate h-step forecast variance
hh
forecast horizon (steps ahead)
TT
number of observations used to fit
SSE\text{SSE}
sum of squared one-step errors over the fit

When to use

  • Short-term forecasting of a series that wanders around a level with no clear trend or seasonality.

Assumptions

  • No systematic trend or seasonal pattern (otherwise use Holt or Holt–Winters).
  • The engine starts from ℓ0=y1\ell_0 = y_1 (the "simple" initialisation) unless an initial level is supplied, and estimates α by minimising the in-sample SSE when α is not given. Prediction intervals assume normal errors and ignore parameter uncertainty, so they are approximate.

How to interpret

  • The weight on the observation jj periods ago is α(1−α)j\alpha(1-\alpha)^j. α near 1 ≈ naive forecast (last value); α near 0 ≈ long-run average.
  • All horizons get the same point forecast; uncertainty grows with hh.

Common mistakes

  • Applying SES to a trending series: forecasts lag systematically behind.
  • Judging α by in-sample fit only — compare methods on a holdout (forecast accuracy).

Example

Series 20, 22, 21, 25, 24 with α = 0.3 and ℓ0=20\ell_0 = 20: levels 20, 20.6, 20.72, 22.00, 22.60. Forecasts for the next two periods are both 22.60; SSE = 26.46.